Now to calculate torques due to different forces,

AC × W = ACWsinθ = τ _{clockwise}

Now from simple geometry rules, we see θ = 20°. (Otherwise, see here).

Therefore,

ACWsin20° = τ_{clockwise}

AB × F_{wall} = ABF_{wall}sin70° = τ_{counterclockwise}

Thus

ACWsin20° = ABF_{wall}sin70° … (C)

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